Learn · Organic Chemistry

Grignard Reagents

Carbon nucleophiles (RMgX) that build C–C bonds by adding to carbonyls.

Quick answer A Grignard reagent (R–MgX) is a carbanion-like carbon nucleophile made from R–X and magnesium in dry ether. Its carbon adds to carbonyls to build a new C–C bond — revealed as an alcohol after acidic workup — but any protic H (O–H, N–H, ≡C–H) destroys it.
Mechanism · Grignard Addition2 steps
Step 1 — the carbanion adds to the carbonyl.
ORRδ+δ−MgBrCH3δ−ORRCH3alkoxide
The C–Mg bond is strongly polarised, so the carbon is a carbanion (δ−). It attacks the δ+ carbonyl carbon, forging a new C–C bond and a magnesium alkoxide.
Step 2 — protonate to the alcohol.
ORRCH3HOH+OHRRCH3alcohol
Aqueous acid protonates the alkoxide. A ketone gives a 3° alcohol, an aldehyde a 2° alcohol, and formaldehyde a 1° alcohol — Grignards build the carbon skeleton.

The Grignard reaction welds two carbon fragments into one new carbon–carbon bond.

A Grignard's carbon adds to a carbonyl; workup reveals an alcohol.

1. A Grignard Is a Carbon Nucleophile — an Umpolung Carbanion

Carbon holds the C–Mg electrons, making it a nucleophilic carbanion — the umpolung reverse of an electron-poor carbonyl carbon.

Carbonyl carbon: δ+ electrophile
The Grignard carbon is the opposite — δ– and electron-rich

2. You Make One from an Alkyl Halide and Magnesium in Dry Ether

Stir an alkyl or aryl halide (R–X) with magnesium in dry ether (Et2O or THF) and Mg inserts into the C–X bond to give R–Mg–X; only the R group matters downstream.

Bromoethane
Iodomethane
Bromobenzene (→ phenyl Grignard)

Each halide plus Mg, Et2O becomes the corresponding R–MgX.

3. Grignards Add to Aldehydes and Ketones to Build C–C Bonds

The Grignard carbon adds to C=O to make an alkoxide; a separate acidic workup (H3O+) then reveals the alcohol.

The electrophilic carbonyl carbon of the aldehyde.
The Grignard's carbon adds, pushing electrons onto oxygen → a magnesium alkoxide.
Acidic workup (H3O+) protonates the alkoxide to the neutral alcohol.

4. The Carbonyl You Start From Fixes the Class of Alcohol

One R always adds, so the starting carbonyl's substitution decides the alcohol class:

  • Formaldehyde (H2C=O) → 1° alcohol.
  • Any other aldehyde → 2° alcohol.
  • Ketone → 3° alcohol.

Formaldehyde → primary alcohol (ethanol).

Acetaldehyde → secondary alcohol (isopropanol).

Acetone → tertiary alcohol (tert-butanol).

5. CO2 Gives a Carboxylic Acid; Epoxides Add Two Carbons

Adding to CO2 caps R with a –COOH (one carbon longer); opening an epoxide gives an alcohol two carbons longer.

CO2 → carboxylic acid (acetic acid), one carbon longer.

Ethylene oxide → primary alcohol, two carbons longer (propan-1-ol).

6. Esters and Acid Chlorides Add Twice to Give 3° Alcohols

The first addition expels the leaving group to unmask a ketone, which is more reactive, so a second equivalent adds — giving a 3° alcohol with two identical R groups.

Methyl acetate + two equivalents of CH3MgBr → a tertiary alcohol (tert-butanol).

7. Any Protic Hydrogen (O–H, N–H, ≡C–H) Destroys a Grignard

This strong base grabs any acidic proton faster than it adds — one drop of water turns R–MgX into useless R–H, as do alcohols, amines, and terminal alkynes.

Water (O–H)
Alcohols (O–H)
Amines (N–H)
Terminal alkynes (≡C–H)

Keep everything dry, add the acidic workup last, and protect any O–H, N–H, or terminal alkyne on your substrate.

8. Summary

R–MgX from R–X + Mg in dry ether · umpolung carbanion · adds to carbonyls for a new C–C bond · formaldehyde → 1°, aldehydes → 2°, ketones → 3° · CO2 → carboxylic acid · epoxides add two carbons · esters/acid chlorides add twice → 3° · dies on any protic H.

1° alcohol
2° alcohol
3° alcohol
Carboxylic acid

Worked example

Problem. What alcohol results from ethylmagnesium bromide + formaldehyde, then acid workup?
  1. The Grignard carbon is a strong nucleophile (δ−); it adds to formaldehyde's carbonyl carbon.
  2. Formaldehyde (H2C=O) always gives a 1° alcohol after workup.
  3. Carbons added: ethyl (2) + the formaldehyde carbon = a three-carbon 1° alcohol.

Answer. Propan-1-ol.

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Carbon is more electronegative than magnesium, so the C–Mg bonding electrons sit on carbon, giving it a partial negative charge (δ). This polarity reversal — umpolung — makes the carbon a carbanion-like nucleophile and strong base, the opposite of an electron-poor carbonyl carbon.

A ketone already has two carbon groups on the carbonyl carbon, so adding the Grignard's R gives a tertiary alcohol. Formaldehyde has only H's, so it gives a primary alcohol. Any other aldehyde falls in between and gives a secondary alcohol.

The Grignard is a very strong base and instantly deprotonates any O–H, N–H, or terminal ≡C–H. Doing so converts R–MgX into the useless alkane R–H and consumes your reagent. That is why the setup must be dry and the acidic workup is added only at the very end.

It adds to CO2 to give a carboxylate that workup protonates to a carboxylic acid. It is useful because it extends the chain by exactly one carbon and installs a –COOH group in a single, predictable step.

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